Question 459700
Assume the problem is:
{{{x/((x^2-2x-3))}}} + {{{5/((x+1))}}}
:
we can factor the 1st denominator to:
{{{x/((x-3)(x+1))}}} + {{{5/((x+1))}}}
:
Therefore the common denominator would be (x-3)(x+1), right?
so we have
{{{(x + 5(x-3))/((x-3)(x+1))}}}
:
Multiply what's inside the brackets:
{{{(x + 5x-15)/((x-3)(x+1))}}} = {{{(6x - 15)/((x-3)(x+1))}}}
:
you can factor out 3 if you want to:
{{{3(2x - 5)/((x-3)(x+1))}}}