Question 47749
Factor completely:
{{{16x^2+40x+25}}} Notice that the first term is a perfect square {{{(4x)^2}}} and the last term is a perfect square {{{(5)^2}}} so it looks like this would factor very nicely.
{{{(4x+5)(4x+5)}}} Check using FOIL
{{{(4x+5)(4x+5) = 16x^2+20x+20x+25}}} Simplify to: {{{16x^2+40x+25}}}