Question 459910
find f(x-1) when f(x)=4x^2+3x+5
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f(x-1) = 4(x-1)^2+3(x-1)+5
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= 4(x^2-2x+1)+3x-3+5
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= 4x^2-8x+4+3x+2
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= 4x^2-5x+6
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cheers,
Stan H.