Question 459917
{{{2^x=64}}}
take log base 2 of both sides
{{{log(2,2^x) = log(2,64)}}}
{{{log(2,2^x) = log(2,2^6)}}}
{{{x = 6}}}
.
2 to the x power equals 100
{{{2^x = 100}}}
{{{log(2,2^x) = log(2,100)}}}
{{{x = log(2,100)}}}
apply "change of base":
{{{x = log(100)/log(2)}}}
{{{x = 6.644}}}
.
10 to the x power equals 12
{{{10^x = 12}}}
{{{x = log(12)}}}
{{{x = 1.079}}}
.
3 to the x power equals 48
{{{3^x = 48}}}
{{{x = log(3,48)}}}
{{{x = log(48)/log(3)}}}
{{{x = 3.524}}}