Question 459825
Find three consecutive even integers such that three times the middle integer is four more than the sum of the first and third?
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1st: 2x-2
2nd: 2x
3rd: 2x+2
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Equation:
3(2x) = 4x+4
6x = 4x+4
2x = 4
x = 2
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1st: 2x-2 = 2
2nd: 4
3rd: 6
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The sum of two number is eighteen. The total of the three times the smaller is equal to the larger. Find the two numbers.
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Equations: 
x + y = 18
3x = y
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Substitute and solve for "x":
x+3x = 18
4x = 18
x = 9/2
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Solve for "y":
y = 18-x
y = (36/2)-(9/2)
y = 27/2
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Cheers,
Stan H.
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