Question 459801


let's the smaller of two consecutive integers be {{{x}}}

and the larger of two consecutive integers be {{{x+1}}}


three times the smaller integer is  {{{3x}}}

four times the larger integer is {{{4(x+1)}}}

If added

{{{3x+4(x+1)=137}}}......solve for {{{x}}}


{{{3x+4x+4=137}}}


{{{7x=137-4}}}


{{{7x=133}}}

{{{x=133/7}}}

{{{x=19}}}.......the smaller integer

{{{x+1=19+1=20}}}.....the larger integer

check:

{{{3x+4(x+1)=137}}}

{{{3*19+4(19+1)=137}}}

{{{57+80=137}}}

{{{137=137}}}