Question 459794
We first write the equation in slope-intercept form {{{y=(-9/2)x-5}}}, as you see 

the slope of the line is m1=-9/2, therefore the slope of the perpendicular line will be m2=2/9, because the perpendicular lines have negative reciprocals slopes.

Now we have to write the equation of the line with slope 2/9 that passes through the point (-9, 9):

{{{y-9=(2/9)(x+9)}}}, writing it in the slope-intercept form we get:

{{{y=(2/9)x+11}}}. See the graph below:

{{{graph(300, 300, -10, 5, -10, 15 , -4.5x-5, 0.222x+11 )}}}