Question 459718
To solve the equation {{{2x=sqrt(10x+6)}}}, we squared both sides of equation

{{{(2x)^2=10x+6}}}, set the equation equal to zero {{{4x^2-10x-6=0}}}, using the 

quadratic formula we find the roots of the equation.

{{{x=(10+-sqrt(10^2-4*4*(-6)))/2*4=(10+-sqrt(196))/8}}}, and the roots are:

{{{x=(10+14)/8=3}}}, and {{{x=(10-14)/8=-1/2}}}.

After checking the roots we reject the root x=-1/2 because it doesn't satisfy the original equation.

Answer: The solution is x=3.

In the same way you can solve the other equations.