Question 459588
A  right  circular  cylinder  is  a  cylinder  whose  base  is perpendicular  to  its  sides (like a soup can.) The expression for the surface area has two parts:
There is the rectangular-shaped side that wraps around the cylinder, and the circular base and top of the cylinder. 
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The surface area of the side is the height of the cylinder times the circumference of the base. In algebra, this translates to
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(h)(2[pi]r) 
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where h is the height of the cylinder and r is the radius of its circular base. We know that the radius is 4 and we approximate [pi] as 3.14. This gives us
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h(2)(3.14)(4) = (25.12)h

The surface area of the base and top of the cylinder is the area of the circle. There are two circles so we multiply by 2.
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(2)([pi])r^2 = (2)(3.14)(4^2) = 100.48
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We combine these expressions to create a polynomial for the surface area S in terms of the height of the cylinder.
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S = (25.12)h + 100.48
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Your question does not include information about the other cylinders, but you can substitute their heights for h in the polynomial and get the surface area.
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Good luck!