Question 47677
A car and a bus leave a town at 1 pm and head for a town 300 miles away. The rate of the car is twice the rate of the bus. The car arrives 5 hours ahead of the bus. Find the rate of the car.

Bus DATA:
distance=300 mi; rate = x mi/hr; time=d/r = (300/x) hr.

Car DATA:
distance=300 mi; rate = rate = 2x mi/hr ; time = d/r = 300(2x) hr.

EQUATIOn:
car time = bus time - 5 hr.

300/2x = 300/x - 5
Divide thru by 300 to get:
1/2x = 1/x - 1/60
Multiply thru by 2x to get:
1 = 2 - x/30
-1=-x/30
x=30
2x=60 mph (The rate of the car)
Cheers,
Stan H.