Question 459524


The width of a rectangle is {{{W=3 ft}}}, 

the length is {{{L=(6x + 2) ft}}}, and 

the area is {{{A=80 ft^2}}} 

Find {{{x}}}:

{{{A=80 ft^2}}}

{{{L*W=80 ft^2}}}

{{{(6x + 2) ft*3 ft=80 ft^2}}}

{{{3(6x + 2) ft^2=80 ft^2}}}

{{{3(6x + 2) cross(ft^2)=80cross( ft^2)}}}

{{{3(6x + 2) =80}}}

{{{18x + 6 =80}}}

{{{18x =80-6}}}

{{{18x =74}}}

{{{x =74/18}}}

{{{x =4.11}}}

so, 

{{{L=(6x + 2) ft=(6*4.11+2)ft=(24.66+2)ft=26.66ft}}}


check:

{{{L*W=80 ft^2}}}

{{{26.66ft*3ft=80 ft^2}}}

{{{79.98ft^2=80 ft^2}}}...round up

{{{80ft^2=80 ft^2}}}