Question 459472


let's {{{3}}} consecutive numbers be: {{{x}}},{{{x+1}}}, {{{x+2}}}

{{{x+(x+1)+(x+2)=105}}}


{{{x+x+1+x+2=105}}}

{{{3x+3=105}}}

{{{3x=105-3}}}

{{{3x=102}}}

{{{x=102/3}}}

{{{x=34}}}.....first number
{{{x+1=35}}}.....second number
{{{x+2=36}}}.....third number


check:

{{{34+35+36=105}}}

{{{105=105}}}