Question 459305
jose left the white house and drove towards the recycling plant an a average speed of 40 km/h. rob left some time later driving in the same direction at an average speed of 48 km/h. after driving 5 hours rob caught up with jose. how long did jose drive before rob caught up.
====================================================================
Jose has a head start on Rob. Let t = Jose's "head start" time
Since Jose's traveling at 40 mph, the initial separation between them is 40t
Their relative speeds = 48 - 40 = 8 km/h
Their separation distance is made up in 5 h.
So we can write 40t = 8 km/h * 5 h
Solving for t gives t = 1 hr.
Therefore, Jose drove a total of 6 hrs.