Question 459254
The parabola {{{f(x)=(1/3)(x+2)^2+1}}}, have for vertex the point (-2, 1), line of 

symetry {{{x=-2}}}, and minimum value {{{y=1/3}}}. See the graph below:

{{{graph(300, 300, -8, 5, -5, 8, 0.333x^2+1.333x+1.7)}}}.