Question 459215
I'll call the parts {{{a}}} and {{{b}}}
(1) {{{ a + b = 4500 }}}
given:
{{{ .05a = .1b }}}
{{{ 5a = 10b }}}
(2) {{{ a = 2b }}}
Substitute (2) into (1)
(1) {{{ 2b + b = 4500 }}}
(1) {{{ 3b = 4500 }}}
(1) {{{ b = 1500 }}}
and
(1) {{{ a + b = 4500 }}}
(1) {{{ a + 1500 = 4500 }}}
(1) {{{ a = 3000 }}}
check answers:
{{{ .05a = .1b }}}
{{{ .05*3000 = .1*1500 }}}
{{{ 150 = 150 }}}
OK