Question 459189
Thanks for the additional information. Here is how to solve for d:
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{{{p=2c+d/3}}}
Subtract 2c from both sides.
{{{p-2c =d/3}}}
Multiply both sides by 3.
{{{3p-6c=d}}}
We can reverse the order of the equation since both sides are equivalent to each other.
{{{d=3p-6c}}}
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I noticed that other students posted a similar problem. I wonder if you meant to use parentheses when you posted your question. Here's a solution to the other problem:
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{{{p=(2c+d)/3}}}
Multiply both sides by 3.
{{{3p=2c+d}}}
Subtract 2c from both sides.
{{{3p-2c=d}}}
Rewrite with d on the left side.
{{{d=3p-2c}}}
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Good luck with you math!