Question 459080
Note: *[Tex \LARGE \left(x_{1}, y_{1}\right)] is the first point *[Tex \LARGE \left(-3,4\right)]. So this means that {{{x[1]=-3}}} and {{{y[1]=4}}}.

Also, *[Tex \LARGE \left(x_{2}, y_{2}\right)] is the second point *[Tex \LARGE \left(5,8\right)].  So this means that {{{x[2]=5}}} and {{{y[2]=8}}}.



{{{m=(y[2]-y[1])/(x[2]-x[1])}}} Start with the slope formula.



{{{m=(8-4)/(5--3)}}} Plug in {{{y[2]=8}}}, {{{y[1]=4}}}, {{{x[2]=5}}}, and {{{x[1]=-3}}}



{{{m=(4)/(5--3)}}} Subtract {{{4}}} from {{{8}}} to get {{{4}}}



{{{m=(4)/(8)}}} Subtract {{{-3}}} from {{{5}}} to get {{{8}}}



{{{m=1/2}}} Reduce



So the slope of the line that goes through the points *[Tex \LARGE \left(-3,4\right)] and *[Tex \LARGE \left(5,8\right)] is {{{m=1/2}}}