Question 458474
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The first thing you need to do is properly express the equation of the given line.  Somewhere there needs to be an equals sign.


Put the given equation into slope-intercept form so that you can determine the slope of the given line by inspection.  Perpendicular lines have slopes that are negative reciprocals.  Calculate the negative reciprocal of the given line to get the slope of the desired perpendicular line.


Use the point-slope form of an equation of a line:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ y\ -\ y_1\ =\ m(x\ -\ x_1) ]


where *[tex \Large \left(x_1,y_1\right)] are the coordinates of the given point and *[tex \Large m] is the calculated slope.


Insert your values, do the arithmetic, reduce the coefficients to lowest terms, and then collect the variable terms in the LHS.


John
*[tex \LARGE e^{i\pi} + 1 = 0]
My calculator said it, I believe it, that settles it
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