Question 458433
Factor the expression:
(x-1)^3+1
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It's the sum of 2 cubes.
Sub y for x-1
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{{{y^3 + 1 = (y+1)*(y^2 - y + 1)}}}
then sub x-1 for y
= {{{x*((x-1)^2 - (x-1) + 1)}}}
= {{{x*(x^2 - 3x + 3)}}}