Question 458431
Solve 2sin3x-1=0 
when -180 <= x <= 180
show all work
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sin(3x) = 1/2
The reference angle is pi/6 and sin is positive in Q1 and QII
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3x = pi/6 or 3x = (5/6)pi
x = pi/18 or x = (5/18)pi
 
>>>>............. 
If cos x = -0.5 find x when 
when -180 <= x <= 180
show all work
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The reference angle is pi/3 and cos is negative in QII and QIII
x = (2/3)pi or x = (4/3)pi
 
>>>> ........... 
I asked for this before but I did not get it >> solve this : 
2sin3x=1 when
0 <= to x <= 90 degrees
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sin(3x) = 1/2
reference angle is 30 degrees and sin is positive in QI and QII
3x = 30 degrees
x = 10 degrees
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Cheers,
Stan H.