Question 458349

2x^3-3x^2-5x=0

=> x(2x^2-3x-5)=0

=> x( 2x^2-5x +2x -5)=0

=> x(x(2x-5)+1(2x-5))=0

=> x(x+1)(2x-5)=0

x = 0, -1 or 5/2