Question 458353
What is the solution to the infinite geometric series... the lower limit is = to 1. The upper limit is the infinite symbol. 0.8(0.2)^(n-1).
<pre>

{{{sum(a[1]r^(n-1),1,infinity) =a[1]/(1-r)}}}

Substitute {{{a[1]=0.8(0.2)^(1-1)=0.8(0.2)^0=0.8(1) = 0.8}}} 
and {{{r = 0.2}}}

{{{sum(0.8(0.2)^(n-1),1,infinity)=0.8/(1-0.2)=0.8/0.8=1}}}

Edwin</pre>