Question 458308
In triangle ACB
a=230 ft
b=110 ft
angle C=34 degrees 
can you help me find side c?
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Use Law of Cosines:
c^2 = a^2+b^2-2abCos(C)
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c^2 = 230^2+110^2-2*230*110*cos(34)
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c^2 = 23050.70
c = 151.82
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Cheers,
Stan H.
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I got 152 is that what you got?
That's what I got.
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