Question 458293
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Your second equation tells you that *[tex \Large 7x\ +\ 77\ =\ y].  So you have this expression in *[tex \Large x] that is equal to *[tex \Large y].  That means that anywhere you see *[tex \Large y] in the first equation, you can replace it with *[tex \Large 7x\ +\ 77], like this:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 7x\ -\ 3(7x\ +\ 77)\ =\ -63]


Now you have a simple linear equation in one variable.  Solve it for *[tex \Large x].  Once you have a value for *[tex \Large x] substitute that value into the second equation and do the arithmetic required to calculate the value of *[tex \Large y].


Finally, represent your answer as an ordered pair *[tex \Large (x,y)] where *[tex \Large x] is the value you determined for *[tex \Large x] above, and *[tex \Large y] is the value you calculated for *[tex \Large y].


John
*[tex \LARGE e^{i\pi} + 1 = 0]
My calculator said it, I believe it, that settles it
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