Question 458265
factor
2x^2 +x -3 = 0
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(2x + ?)(x - ?) = 0
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Well the factors of 3 are 1 and 3.
So, does that work or do we have to use the quadratic equation?
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(2x+3)(x-1) = 0
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So the solutions are x=1 or -3/2.
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The graph is
{{{graph(500,500,-5,5,-5,5,2*x*x +x -3)}}}