Question 458255
The half-life of lead is 22 yr. What is the decay rate? 
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Let "r" be the remainder rate :
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Solve: (1/2)Ao = Ao(r)^22)
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r^22 = (1/2) 
r = 0.5^(1/22)
r = 0.97
Decay rate = 1-0.97 = 3%
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Cheers,
Stan H.