Question 458117
Find the smallest angle of a triangle whose sides are 7, 8, and 9. (solution in radians)
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The smallest angle is opposite the shortest side
Use the Cosine Law.
{{{7^2 = 8^2 + 9^2 - 2*8*9*cos(A)}}}
cos(A) = (64 + 81 - 49)/144 = 96/144
A =~ 0.84107 radians