Question 458205
the square of the difference of 6 and a number is 4 less than the number
..
let x=number
(6-x)^2=x-4
36-12x+x^2=x-4
x^2-13x+40=0
(x-8)(x-5)=0
x-8=0
x=8
or 
x-5=0
x=5
ans:
The number could be 8 or 5