Question 458185
Solve x^3+4x^2-12x by factoring
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 x^3+4x^2-12x=0
x(x^2+4x-12)=0
x(x+6)(x-2)=0
x=0
x+6=0
x=-6
x-2=0
x=2
ans:
x=0, -6 or 2
see graph below as visual evidence of answers
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{{{ graph( 300, 300, -10, 10, -10, 10,x^3+4x^2-12x) }}}