Question 458121
The distance between each of the bases on a baseball diamond is 90ft.
 A catcher often has to throw from home to 2nd base in order to get a player who is stealing bases out.
 How far does a catcher have to throw in this situation?
:
Solve this as a right triangle, the distance from home to 2nd is the hypotenuse(c), so you have:
:
c = {{{sqrt(90^2+90^2)}}}
c = 127.28 ft from home to 2nd