Question 5927
 There are 5 possible numbers of a kind,the prob. is 5/6^5 = 5/1296 (use math notation, not regular English)

 Among 5 dices, 2 of them are the same number, then 2 of the remaining 3 are
 te same, the fifth one shouldbe different from the preevious two numbers.

 There are 6*C(5,2)*5*C(3,2)*4 = 6*10*5*3*4 = 3600
 So the prob. of 2 pairs is 3600/6^5 = 100/6^3 = 25/54 (use fraction
 no decimals)

 Kenny