<PRE><B>Question 457855</B>
The table below describes the smoking habits of a group of asthma sufferers.

	non smoker	light smoker	heavy smoker	total
men	350.....	88......	82......	520
women	334.....	70......	84......	488
total	684.....	158.....	166.....	1008

A person is randomly selected. If the person selected is a light smoker, what is the probability that it is a woman?
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This is a conditional probability problem.
P(woman | light smoker) 
= [P(woman AND light smoker)]/P(light smoker)]
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= 70/1008 / 158/1008
= 70/158
= 0.4430
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Notice: You get the answer faster by simply dividing the
number of light-smoker women by the # of light smokers
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Cheers,
Stan H.


A) 0.069        B) 0.143        C) 0.443        D) 0.257
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