Question 457848
{{{y=(1/3)^x}}}...>.....{{{y=3^(-x)}}}, 

and {{{y=3(1/2)^x}}}...>.....{{{y=3*2^(-x)}}}

just plug in some values for {{{x}} and find {{{y}}}

{{{y=3^(-x)}}}

x|y
0|1
1|1/3........{{{y=3^(-1)=1/3}}}
2|1/9........{{{y=3^(-2)=1/9}}}
:
:
connect the points and do same for {{{y=3*2^(-x)}}} and you will have lines like this: 


{{{ graph( 500, 500, -6, 5, -10, 10, (1/3)^x, 3(1/2)^x) }}}


{{{y=3^(-x)}}}....red

{{{y=3*2^(-x)}}}..green