Question 457722


the area of a rectangle is {{{A=ab}}}

let {{{A=12 y^3+6y^2+4y}}} and one dimension {{{a= 2y}}}

find {{{b}}}

{{{A=ab}}}

{{{b=A/a}}}

{{{b=(12 y^3+6y^2+4y)/2y}}}

{{{b=2y(6y^2+3y+2)/2y}}}

{{{b=cross(2y)(6y^2+3y+2)/cross(2y)}}}


{{{b=6y^2+3y+2}}}...solution