Question 457676

in case you have this:

Evaluate {{{sqrt(b^2)-4ac }}}if {{{a=-5}}}, {{{b=-4}}}, {{{c=60}}}

{{{sqrt(b^2)-4ac=sqrt((-4)^2)-4*(-5)*60=sqrt(16)+20*60=4+1200=1204 }}}

but, in case you have this:

{{{sqrt(b^2-4ac)=sqrt((-4)^2-4*(-5)*60)=sqrt(16+1200)=sqrt(1216)=34.87 }}}