Question 457641
Let's make the two numbers x and y.
{{{x * y = 90}}}
.
Let's say x is 3 more than y.
{{{x = y + 3}}}
or
{{{x - 3 = y}}}
Either way you prefer.
.
Substituting the value of y.
{{{x * (x-3) = 90}}}
.
Multiply through
{{{x^2 -3x = 90}}}
.
Subtract 90 from both sides.
{{{x^2 -3x -90 = 0}}}
.
Done.