Question 457422
The way you have written your original problem is log 2 - 5x/2(x+8) = 0.  Written in this way, the problem according to the rules of algebra should be interpreted as follows:
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{{{log2-5x/2(x+8) = 0}}}
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However, this is not the problem that you worked. From what you worked you probably meant to write the problem in algebraic form as log((2-5x)/(2*(x+8))) and that is correctly interpreted as:
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{{{log((2-5x)/(2*(x+8)))=0}}}
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Assuming that this second interpretation is correct, you proceeded correctly. Your methodology is correct down to the point where you had:
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{{{2-5x = 2x + 16}}}
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Somewhere in here you made a minor sign error.  Subtract 2 from both sides and you have:
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{{{-5x = 2x + 14}}}
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Then subtract 2x from both sides to get:
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{{{-7x = 14}}}
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Finally, divide both sides by -7 and you arrive at the answer:
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{{{x = -2}}}
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You indicated that your answer was 2 (presumed to be x = +2).  That is perhaps why you are having trouble checking your answer with a calculator.
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You can return to your problem and substitute -2 for x and you will get:
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{{{log (12/12)=0}}}
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This is correct because {{{log(12/12) = log(1)}}} and {{{log(1) = 0}}}
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Hope this helps. Make sure that you fully understand how to write algebraic expressions in line form and that operations are performed from left to right within parentheses first, then exponents, then multiplication and divisions as encountered left to right and finally additions and subtractions left to right as encountered. It can make quite a difference in correctly interpreting the problem as you can see from the two forms above.