Question 457441
{{{5^(x-6)=29}}}
we take log base 5 of both sides:
{{{log(5,5^(x-6)) = log(5,29)}}}
{{{x-6 = log(5,29)}}}
apply "change of base"
{{{x-6 = log(29)/log(5)}}}
{{{x = log(29)/log(5) + 6}}}
{{{x = 2.092 + 6}}}
{{{x = 8.092}}}