Question 457328

{{{8t/(t^2 - 16) + t/(t-4)}}}


={{{8t/(t^2 - 4^2) + t/(t-4)}}}


={{{8t/((t -4)(t +4)) + t/(t-4)}}}


={{{(8t + t(t +4))/((t -4)(t +4))}}}


={{{(8t + t^2 +4t)/((t -4)(t +4))}}}


={{{(t^2 +12t)/((t -4)(t +4))}}}


={{{t(t +12)/((t -4)(t +4))}}}