Question 457262
{{{ x^2 - x - 12 = 0 }}}
{{{ (x - 4)*(x + 3) = 0 }}}
The roots are 
{{{ x = 4 }}}
{{{ x = -3 }}}
The possibilities are:
{{{ p + 1 = 4 }}}
{{{ q + 1 = -3 }}}
which gives {{{ p = 3 }}}, {{{ q = -4 }}}
or
{{{ p + 1 = -3 }}}
{{{ q + 1 = 4 }}}
which gives {{{ p = -4 }}}, {{{ q = 3 }}}