Question 47100
first we can rewrite 1 as log2(2), so we will have an equation:
log2(x+2) = log2(2) + log2(x-5) 
log2(x+2) = log2(2x-10), so we will recieve an equation
x+2 = 2x-10
x = 12

conditions:  x+2 > 0 => x > -2   &  x-5 > 0 => x > 5, so x must be grater than 5
12 > 5, so it is correct solution