Question 456944
Draw the parabola. Identify the focus and directrix and show them on the graph.
x+1/4y^2=0
Also find the 
focus: 
Directrix:
..
x+1/4y^2=0
y^2/4=-x
y^2=-4x
..
Standard form for parabola: (y-k)^2=4p(x-h), with (h,k) being the (x,y) coordinates of the vertex.
For given parabola:
vertex at (0,0)
Axis of symmetry, y=0 or x-axis
Parabola opens leftward
4p=4
p=1
focus, (-1,0)
directrix, x=1
see following graph as a visual check on the answers.
..
y=(-4x)^.5
{{{ graph( 300, 200, -6, 5, -10, 10, (-4x)^.5,-(-4x)^.5) }}}