<PRE><B>Question 457210</B>
9th rt b^2 * sqrt b^9
I get this
b^2/9 b^9/2=b^2/18 b^9/18
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If what you say is correct you should add the
exponents to get b^(11/9)
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from here I am confused. It shows in help that it is b^85/18.
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To get 85/18 you would nee 9/2 + 2/9 = (81+4)/18 = 85/18
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Maybe your problem is not what you posted but rather:
sqrt(b^9)* 9th rt. of b^2
which would give you
b^(9/2) * b^(2/9) = b^(9/2 + 2/9) = b^(85/18)
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Cheers,
Stan H. </PRE>