Question 457191
By moving all terms to one side:
2x^2=-6+8x
2x^2 - 8x =-6
2x^2 - 8x + 6 = 0
you could divide both sides by 2 to get:
x^2 - 4x + 3 = 0
Now, you can apply the "quadratic formula".
BUT in this case, it is easier to factor:
(x-1)(x-3) = 0
x = {1,3}