Question 457185
{{{9x^3-18x^2-16x+32}}}

={{{(9x^3-18x^2)-(16x-32)}}}

={{{9x^2(x-2)-16(x-2)}}}

={{{(9x^2-16)(x-2)}}}

={{{((3x)^2-4^2)(x-2)}}}

={{{(3x-4)(3x+4)(x-2)}}}.......if any factor is equal to zero, whole product will be equal to zero

so, the roots are:

{{{3x-4=0}}}....->.......{{{3x=4}}}....->.......{{{x=4/3=1.33}}}

{{{3x+4=0}}}....->.......{{{3x=-4}}}....->.......{{{x=-4/3=-1.33}}}

{{{x-2=0}}}....->.......{{{x=2}}}


{{{ graph( 500, 500, -10, 20, -10, 50, 9x^3-18x^2-16x+32) }}}