Question 47530
find the area of a box with dimensions sqrt 3 + sqrt 5 (length) and sqrt 3 + sqrt 5 (height)

Use FOIL as follows:
F: sqrt3 * sqrt3 = 3
O: sqrt3 * sqrt5 = sqrt15
I: sqrt5 * sqrt3 = sqrt15
L: sqrt5 * sqrt% = 5

Combine to get:
8 + 2sqrt(15)

Cheers,
Stan H.