Question 457180


If {{{z=32}}}, than the value of {{{z^1/5+ 2z^0+ (8z)^-1/2=root(5,32)+ 2*32^0+1/sqrt(8*32)=root(5,2^5)+ 2*1+1/sqrt(256)=2+ 2+1/16=4+0.0625=4.0625}}}