Question 457079
{{{(x-3)(2x-7)=0}}}...here you have a quadratic equation already factored; so the roots will be:

if {{{x-3=0}}}...->...{{{x=3}}}

and

if {{{2x-7=0}}}...->...{{{2x=7}}}...->...{{{x=7/2=3.5}}}

let's see it on a graph:

{{{(x-3)(2x-7)=0}}}

{{{2x^2-7x-6x+21=0}}}

{{{2x^2-13x+21=0}}}


{{{ graph( 500, 500, -30, 15, -15, 30, 2x^2-13x+21) }}}