Question 47511
N(t)=N(o)e^-0.02t  How many days (to the nearest tenth ofa day) will it take for 50% of the wound to heal?

50% of N(o) = 0.5N(o)

0.5N(o) = N(o)e^(-0.02t)
0.5 = e^(-0.2t)
Take the natural log to get:
-0.2t=ln(0.5)
-0.2t=-0.6931...
t=3.5 days
Cheers,
Stan H.