Question 456931
A sample of 100 elements produced a mean of 84 and a standard deviation of 8. Find the 99% confidence interval for the population mean. Assume the population is normally distributed.
----
sample mean = 84
Margin of Error = ME = 2.5758*8/sqrt(100) = 2.0607
------------------------------
99% CI: 84-2.0607 < u < 84+2.0607
----
99% CI: 81.94 < u < 86.06
============================================
Cheers,
Stan H.
===========